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$$AB$$ is parallel to $$CD$$ and the two slanting lines carrying the arrow marks are parallel to each other. Using corresponding angles on the transversal through $$C$$ and $$E$$, the angle at $$C$$ above the line $$CD$$ is $$85^\circ$$, and alternate angles with $$AB$$ parallel to $$CD$$ give $$41^\circ$$ for the part of it lying above $$CD$$. Hence $$x = 180^\circ - 85^\circ - 41^\circ = 54^\circ$$.
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