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Question 2
In quadrilateral PQRS, PQ = 5 units, QR = 17 units, RS = 5 units, and PS = 9 units. The length of the diagonal QS can be:
Solution
In a triangle , sum of two sides is greater than the third side and difference of two sides is less than third side.
In $$\triangle$$ PQS
=> $$QS < 9 + 5$$ => $$QS < 14$$ ------Eqn(I)
In $$\triangle$$ QRS
=> $$QS > 17 - 5$$ => $$QS > 12$$ ------Eqn(II)
From eqn(I) & (II)
=> $$12 < QS < 14$$
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