If $$a^{2}+b^{2}=80$$ and $$ab=32$$, then calculate the value of $$\frac{a-b}{a+b}$$
Given : $$a^{2}+b^{2}=80$$ ----------(i) and $$ab=32$$
=> $$2ab=64$$ -----------(ii)
Adding equations (i) and (ii), we get :
=> $$a^2+b^2+2ab=80+64$$
=> $$(a+b)^2=144$$
=> $$(a+b)=\sqrt{144}=12$$
Similarly, $$(a-b)=4$$
$$\therefore$$Â $$\frac{a-b}{a+b}$$
= $$\frac{4}{12}=0.333$$
=> Ans - (C)
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