Question 19
The following table gives the details of the number of students in Class 10 section A and B who had taken mid-term and final exam.
The percentage of students in section A of class 10 is (round to one decimal).
Solution
Total number of students in section A =$$28+14+6+64=112$$
Total number of students in section B =$$23+12+17+55=107$$
Total number of students in class 10 = $$112+107=219$$
percentage of students in section A =$$\frac{112}{219}\times100=51\cdot1$$%
Hence option (B) is right answer.
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