A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ........
Here, work done by the body will be kinetic energy provided by given force.
We haveÂ
$$M=4.0kg$$
$$V=5ms^{-1}$$
K.E. =Â $$\frac{1}{2}mv^2$$
    =$$\frac{1}{2}\times4.0\times5^{2}$$
    = 50 J  Â
Hence Option (A) is right answer.              Â
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