Get 10 SSC CHSL Mocks at just Rs. 117. Enroll here
Exam Info
Free Content
Study Material
Courses
AP
TS
The discharge over a shape edge triangular notch having included angle of 2\theta and the depth of h is given by formula
$$\frac{2}{3} C_{d} \sqrt{2g} \tan \theta h^{\frac{3}{2}}$$
$$\frac{8}{15} C_{d} \sqrt{2g} \tan \theta h^{\frac{3}{2}}$$
$$\frac{2}{3} C_{d} \sqrt{2g} \tan \theta h^{\frac{5}{2}}$$
$$\frac{8}{15} C_{d} \sqrt{2g} \tan \theta h^{\frac{5}{2}}$$
Create a FREE account and get:
Ask doubts feature is currently unavailable for you. You can reach us at support@cracku.in for any further details/doubts.
Boost your Prep!
