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The discharge over a shape edge triangular notch having included angle of 2\theta and the depth of h is given by formula
$$\frac{2}{3} C_{d} \sqrt{2g} \tan \theta h^{\frac{3}{2}}$$
$$\frac{8}{15} C_{d} \sqrt{2g} \tan \theta h^{\frac{3}{2}}$$
$$\frac{2}{3} C_{d} \sqrt{2g} \tan \theta h^{\frac{5}{2}}$$
$$\frac{8}{15} C_{d} \sqrt{2g} \tan \theta h^{\frac{5}{2}}$$
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