The angles of elevation of the top of a tower of height 80 when observed from two points A, B on the level ground which are on either side of the tower and collinear with the foot of the tower are respectively $$30^{\circ}$$ and $$45^{\circ}$$ then the distance between A and B in meters) is

A

$$80(\sqrt{3} + 1)$$

B

$$\frac{80(\sqrt{3} + 1)}{\sqrt{3}}$$

C

$$80(\sqrt{3} - 1)$$

D

$$\frac{80(\sqrt{3} - 1)}{\sqrt{3}}$$