If permissible compressive stress in concrete is 50 kg/cm$$^2$$, tensile stress in steel is 1400 kg/cm$$^2$$ and modular ratio is 18, the depth of the beam is
1] $$d = \sqrt{\frac{0.11765 \times B.M}{breadth}}$$
2] $$d = \sqrt{\frac{0.22765 \times B.M}{breadth}}$$
3] $$d = \sqrt{\frac{0.33765 \times B.M}{breadth}}$$
4] $$d = \sqrt{\frac{0.44765 \times B.M}{breadth}}$$
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