Question 18

There is a copper wire of 1 cm diameter and 8 cm length. It is moulded in a wire of 18 cm length. What would be the diameter of this new wire ?

Solution

Assuming the volume of the wire remains constant. $$ \pi d ^ {2} \frac{h}{4} = \pi D ^ {2} \frac{H}{4}$$

So, $$ D ^ {2} = 1 \times \frac {8}{18} $$

So, D = 2/3

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