Question 18
There is a copper wire of 1 cm diameter and 8 cm length. It is moulded in a wire of 18 cm length. What would be the diameter of this new wire ?
Solution
Assuming the volume of the wire remains constant. $$ \pi d ^ {2} \frac{h}{4} = \pi D ^ {2} \frac{H}{4}$$
So, $$ D ^ {2} = 1 \times \frac {8}{18} $$
So, D = 2/3
Get AI Help
Create a FREE account and get:
- Download RRB Study Material PDF
- 45+ RRB previous papers with solutions PDF
- 300+ Online RRB Tests for Free
