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The sum of three consecutive odd numbers is always divisible by:
A. 2
B. 3
C. 5
D. 6
Choose the correct answer from the options given below:
Let the odd numbers be:Β 2n+1, 2n+3, 2n+5.
Their sum will be:Β 2n+1 + 2n+3 + 2n+5 = 6n+9
==> 3*(2n+3).
So, the sum is always divisible by 3 only i.e. Option D.
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