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The Nucleus $$^{23}_{10}\text{Ne}$$ decays by $$\beta^-$$ emission through the reaction $$^{23}_{10}\text{Ne} \rightarrow\ ^{23}_{11}\text{Na} + ^{0}_{-1}\beta + \bar{\nu} + $$ energy. The atomic masses are $$^{23}_{10}\text{Ne} = 22.994466$$ u and $$^{23}_{11}\text{Na} = 22.989770$$ u, and $$^{0}_{-1}\beta = 0.000549$$ u. The maximum kinetic energy that the emitted electron can ever have is
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