Question 175

The area of the triangle formed by the graphs of the equations x= 0, 2x+ 3y= 6 and x+ y= 3 is :

Solution

AC represents $$x+y=3$$

BC represents $$2x+3y=6$$

AB represents $$x=0$$

=> ABC is the required triangle.

Base AB = 1 unit and height OC = 3 units

=> Area of $$\triangle$$ABC = $$\frac{1}{2}$$ * AB * OC

= $$\frac{1}{2}$$ * 1 * 3 = 1$$\frac{1}{2}$$ sq. unit


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