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Question 175
The area of the triangle formed by the graphs of the equations x= 0, 2x+ 3y= 6 and x+ y= 3 is :
Solution
AC represents $$x+y=3$$
BC represents $$2x+3y=6$$
AB represents $$x=0$$
=> ABC is the required triangle.
Base AB = 1 unit and height OC = 3 units
=> Area of $$\triangle$$ABC = $$\frac{1}{2}$$ * AB * OC
= $$\frac{1}{2}$$ * 1 * 3 = 1$$\frac{1}{2}$$ sq. unit
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