IBPS Clerk 11-Dec-2011 NZ 1st

Question 175

$$21 \times 24 - (4)^{3} + 7^{2} - (?) = 19^{2}$$

Solution

(21 *24) - 64 + 49 - x = 361

504 - 64 + 49 - x = 361

489 - x = 361

x = 489 - 361 = 128

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