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$$(3^{2} \times 4^{2} \times 5) \div 36 = (?)^{2} - 80$$
$$(100)^{2}$$
156
100
1.0
$$10\sqrt{10}$$
$$(3^{2} \times 4^{2} \times 5) \div 36 = (?)^{2} - 80$$$$(9\times 16 \times 5) \div 36 = (?)^{2} - 80$$$$(720) \div 36 = (?)^{2} - 80$$$$20+80 = (?)^{2} $$? = -10 or 10
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