Question 169

$$2\frac{1}{9} \times 1\frac{2}{19} \div 2\frac{1}{3} = ? - 1\frac{1}{2}$$

Solution

Let the unknown be $$x$$.
$$2\frac{1}{9} = \frac{19}{9}$$ , $$1\frac{2}{19}$$ = $$\frac{21}{19}$$ , $$2\frac{1}{3}$$ =$$ \frac{7}{3}$$ , $$1\frac{1}{2}$$=$$\frac{3}{2}$$

$$\frac{21}{19} \div \frac{7}{3}$$ =$$ \frac{9}{19}$$

$$\frac{19}{9} \times \frac{9}{19}$$ =$$1$$
$$1 = x - \frac{3}{2}$$
$$x = 1 + \frac{3}{2}$$
$$x=\frac{5}{2} = 2\frac{1}{2}$$
Hence Option C is the correct answer.


Create a FREE account and get:

  • Banking Quant Shortcuts PDF
  • Free Banking Study Material - (15000 Questions)
  • 135+ Banking previous papers with solutions PDF
  • 100+ Online Tests for Free

cracku

Boost your Prep!

Download App