$$2\frac{1}{9} \times 1\frac{2}{19} \div 2\frac{1}{3} = ? - 1\frac{1}{2}$$
Let the unknown be $$x$$.
$$2\frac{1}{9} = \frac{19}{9}$$ , $$1\frac{2}{19}$$ = $$\frac{21}{19}$$ , $$2\frac{1}{3}$$ =$$ \frac{7}{3}$$ , $$1\frac{1}{2}$$=$$\frac{3}{2}$$
$$\frac{21}{19} \div \frac{7}{3}$$ =$$ \frac{9}{19}$$
$$\frac{19}{9} \times \frac{9}{19}$$ =$$1$$
$$1 = x - \frac{3}{2}$$
$$x = 1 + \frac{3}{2}$$
$$x=\frac{5}{2} = 2\frac{1}{2}$$
Hence Option C is the correct answer.
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