Question 17
The maximum length of a pencil that can be kept in a rectangular box of dimensions 8 cm x 6 cm x 2 cm, is
Solution
The maximum length of pencil will be along the longest diagonal of box
so we can say the maximum length will be : $$\sqrt{\ 4^2+6^2+8^2}=\sqrt{\ 104}\ =2\sqrt{\ 26}$$
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