Question 17

If A is 28% more than B and C is 25% less than the sum of A and B. Then by what percent will C be more than A (correct to one decimal place)?

Solution

Let the B = 100
A = 128
C = 25% less than the sum of A and B
C = (100 + 128) $$\times \frac{75}{100}$$ = 171
Required percentage =$$ \frac{171 - 128}{128} \times 100 = \frac{43}{128} \times 100$$ = 33.6%
$$\therefore$$ The correct answer is option D.

Create a FREE account and get:

Free SSC Study Material - 18000 Questions
230+ SSC previous papers with solutions PDF
100+ SSC Online Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Profit And Loss Questions CAT Arithmetic Questions CAT Coordinate Geometry Questions CAT Quadratic Equations Questions CAT Probability, Combinatorics Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Selection With Condition Questions CAT DI Miscellaneous Questions CAT Coins and Weights Questions CAT Venn Diagrams Questions CAT Charts Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Grammar and Sentence Correction Questions CAT Para Summary Questions CAT Verbal Ability Questions CAT Reading Comprehension Questions CAT Miscellaneous Questions

SSC CGL Tier-2 11th September 2019 Maths

If A is 28% more than B and C is 25% less than the sum of A and B. Then by what percent will C be more than A (correct to one decimal place)?

CAT Quant Questions | CAT Quantitative Ability

CAT DILR Questions | LRDI Questions For CAT

CAT Verbal Ability Questions | VARC Questions For CAT

Free Quant Questions

Login to your Cracku account

Hello! 👋

Ready to Unlock Your Success?

Please Enter Your OTP

Please enter the following details

Create a free Cracku account