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Question 17
If A is 28% more than B and C is 25% less than the sum of A and B. Then by what percent will C be more than A (correct to one decimal place)?
Solution
Let the B = 100
A = 128
C =Â 25% less than the sum of A and B
C = (100 +Â 128) $$\times \frac{75}{100}$$ = 171
Required percentage =$$ \frac{171 - 128}{128} \times 100 = \frac{43}{128} \times 100$$ = 33.6%
$$\therefore$$ The correct answer is option D.
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