Question 17

All sides of a quadrilateral ABCD touch a circle. If AB = 6 cm. BC = 7.5 cm. CD = 3 cm, then DA is

Solution

Given : AB = 6 cm. BC = 7.5 cm. CD = 3 cm

To find : DA = ?

Solution : Tangents from the same point to a circle are equal in length.

=> $$AE=AH$$, $$BE=BF$$, $$CG=CF$$ and $$DG=DH$$

Adding above equations, we get :

=> $$(AE+BE)+(CG+DG)=(BF+CF)+(AH+DH)$$

=> $$AB+CD=BC+DA$$

=> $$6+3=7.5+DA$$

=> $$DA=9-7.5=1.5$$ cm

=> Ans - (D)

Create a FREE account and get:

Free SSC Study Material - 18000 Questions
230+ SSC previous papers with solutions PDF
100+ SSC Online Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Remainders Questions CAT Time, Distance and Work Questions CAT Time Speed Distance Questions CAT Profit, Loss and Interest Questions CAT Venn Diagrams Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Selection With Condition Questions CAT Miscellaneous LR Questions CAT Truth Lie Concept Questions CAT Data change over a period Questions CAT Scheduling Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Para Jumbles Questions CAT Odd One Out Questions CAT Vocabulary Questions CAT Para Summary Questions CAT Critical Reasoning Questions

Follow us on

Boost your Prep!

Download App