Question 16
In the adjoining figure, $$ABCD$$ is a rectangle. Then $$\angle EBD$$ is ______ degrees.
Correct Answer: 12
Solution
Since the corner at $$B$$ is a right angle and the marked angle at $$E$$ is $$70^\circ$$, $$\angle ABE=90^\circ-70^\circ=20^\circ$$. Also, $$\angle DBC=58^\circ$$. Therefore $$\angle EBD=90^\circ-20^\circ-58^\circ=12^\circ$$.
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