Instructions

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a<b

b) $$a\leq b$$

c) relationship between a & b cannot be established

d) a>b

e) $$a\geq b$$

Question 16

I.$$2a^{2}+a-1=0$$
II.$$12b^{2}-17b+6=0$$

Solution

$$2a^{2}+a-1=0$$
We get the factor as:
a=-1, a=0.5

$$12b^{2}-17b+6=0$$
Solving, we get the factor as,
a= .66, b= .75

Hence, b>a
Option A is the correct option.

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I.$$2a^{2}+a-1=0$$ II.$$12b^{2}-17b+6=0$$

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I.$$2a^{2}+a-1=0$$
II.$$12b^{2}-17b+6=0$$