Instructions

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a<b

b) $$a\leq b$$

c) relationship between a & b cannot be established

d) a>b

e) $$a\geq b$$

Question 17

I.$$a^{2}-5a+6=0$$
II. $$2b^{2}-13b+21=0$$

Solution

Soving the quadratic equations we get,
$$a^{2}-5a+6=0$$
i.e (a-2)(a-3)=0
i.e a=2, a=3

$$2b^{2}-13b+21=0$$
i.e (b-3.5)(b-3)=0
i.e b= 3.5 and b=3

Hence, we can deduce that $$a\leq b$$
Therefore, option B is correct.

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I.$$a^{2}-5a+6=0$$ II. $$2b^{2}-13b+21=0$$

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I.$$a^{2}-5a+6=0$$
II. $$2b^{2}-13b+21=0$$