In an auto-transformer of voltage ratio $$\frac{V_{1}}{V_{2}},V_{1}>V_{2}$$, the fraction of power tranferred inductively is proportional to

A

$$\frac{V_{1}}{(V_{1}+V_{2})}$$

B

$$\frac{V_{2}}{V_{1}}$$

C

$$(V_{1}-V_{2})(V_{1}+V_{2})$$

D

$$\frac{(V_{1}-V_{2})}{V_{1}}$$