A shipping clerk has five boxes of different but unknown weights each weighing less than 100 kgs. The clerk weighs the boxes in pairs. The weights obtained are 110, 112, 113, 114, 115, 116, 117, 118, 120 and 121 kgs. What is the weight, in kgs, of the heaviest box?
Let the individual weights be a,b,c,d,e in increasing order such that e is max and a is min. Adding all the addition of weight together we get 4*(a+b+c+d+e) = 1156 so a+b+c+d+e = 289 . Out of these a+b will be lowest sum and d+e will be the max . so a+b=110 and d+e=121 so we get value of c as 58 . now c have the 3rd highest weight so addition of c and e must give the second largest total i.e 120 . hence e = 120-58 = 62
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CEO CAT
2Â weeks, 2Â days ago
62,59,58,56,54
Aman Kumar
7Â months ago
The above solution is wrong as upon adding the paired weights from 110, 112,….till 121 we get 1275 not 1154. Please look into this.
Rishabh Sahu
2Â months ago
You added 119 in your addition
PRISITA DUTTA
2Â years, 10Â months ago
Where did that 4 come from?
Amit Kumar
1Â year, 9Â months ago
Where is it written boxes are counted 4 times
Kumar Aakash
2Â years, 9Â months ago
each box has been weighted 4 time