Question 152

$$\frac{414 \div 23 \times 7 + 36}{7^{2}+(3^{2}-2^{2})}=?$$

Solution

$$\frac{414 \div 23 \times 7 + 36}{7^{2}+(3^{2}-2^{2})}$$

$$\frac{18 \times 7 + 36}{7^{2}+(3^{2}-2^{2})}$$

$$\frac{126 + 36}{7^{2}+(3^{2}-2^{2})}$$

$$\frac{162}{7^{2}+(3^{2}-2^{2})}$$

$$\frac{169}{49+5}$$

= 3

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