Instructions

In each of the following questions, which of the following interchange of signs would make the given equation correct ?

Question 151

$$10+10\div10-10\times10=10$$

Solution

Expression : $$10+10\div10-10\times10=10$$

(A) : $$10-10\div10+10\times10$$

= $$10-1+100=109\neq10$$

(B) : $$10\div10+10-10\times10=10$$

= $$1+10-100=-89\neq10$$

(C) : $$10\times10\div10-10+10=10$$

= $$10-10+10=10$$

(D) : $$10\div10+10-10\times10=10$$

= $$1+10-100=-89\neq10$$

=> Ans - (C)

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