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If the equation $$x^3 - ax^2 + bx - a = 0$$ has three real roots, then it must be the case that,
b $$\neq$$ 1
a $$\neq$$ 1
It can be clearly seen that if b=1 then $$x^2(x - a) + (x - a) = 0$$ an the equation gives only 1 real value of x
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