If 43x + 43y = 4816, what is the average of x and y ?
Given : $$43x + 43y = 4816$$
=> $$43 (x + y) = 4816$$
=> $$x + y = \frac{4816}{43} = 112$$
$$\therefore$$ Required average
=> $$\frac{x + y}{2} = \frac{112}{2} = 56$$
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