$$\frac{2560}{32}+\frac{23}{45} of 855 = \frac{7}{11} of ? + 391$$

Solution

Expression : $$\frac{2560}{32}+\frac{23}{45} of 855 = \frac{7}{11} of ? + 391$$

=> $$80 + (\frac{23}{45} \times 855) = (\frac{7}{11} \times x) + 391$$

=> $$80 + (23 \times 19) = \frac{7x}{11} + 391$$

=> $$80 + 437 - 391 = \frac{7x}{11}$$

=> $$\frac{7x}{11} = 126$$

=> $$x = \frac{126 \times 11}{7}$$

=> $$x = 18 \times 11 = 198$$

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