Question 15

Some carpenters promised to do a job in 15 days but 3 of them were absent and remaining did the job in 20 days. What was the original number of carpenters?

Solution

Let original number of carpenters = $$x$$

Using, $$M_1D_1=M_2D_2$$

=> $$x\times15=(x-3)\times20$$

=> $$15x=20x-60$$

=> $$20x-15x=60$$

=> $$x=\frac{60}{5}=12$$

$$\therefore$$ Original number of carpenters = 12

=> Ans - (C)

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