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If 17@1=8; 9@1=4; 6@4=1; then what is the value of 8@2=?
The pattern followed is that for $$a$$@$$b$$ = $$\frac{(a-b)}{2}$$
Eg : 17@1 = $$\frac{17-1}{2}=\frac{16}{2}=8$$
and 9@1 = $$\frac{9-1}{2}=\frac{8}{2}=4$$
and 6@4 = $$\frac{6-4}{2}=\frac{2}{2}=1$$
Similarly, 8@2 = $$\frac{8-2}{2}=\frac{6}{2}=3$$
=> Ans - (A)
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