Question 145
The area of a trapezium is 105 sq. m and, the lengths of its parallel sides are 9m and 12m respectively. Then the height of the trapezium is
Solution
Area of trapezium = $$\frac{1}{2}$$*(sum of parallel sides)*(height)
=> $$\frac{1}{2}*(9 + 12)*h = 105$$
=> $$h = \frac{105 * 2}{21}$$
=> $$h = 10 m$$
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