Question 143
The three equal circles touch each other externally. If the centres of these circles be A, B, C then ABC is
Solution
Since all the three circles are equal, let radius of each be $$r$$
=> AD = DB = $$r$$
=> AB = AD + DB = $$2r$$
Similarly, BC = AC = $$2r$$
Since, all sides are equal, => ABC is an equilateral triangle.
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