$$PQR$$ is a triangle. The bisectors of the internal angle $$\angle Q$$ and external angle $$\angle R$$ intersect at $$S$$. If $$\angle QSR = 40^{\circ}$$, then $$\angle P$$ is:

A

$$40^{\circ}$$

B

$$60^{\circ}$$

C

$$80^{\circ}$$

D

$$30^{\circ}$$