$$(3\frac{6}{17}+2\frac{7}{34}-1\frac{9}{25})= (1) (?)^{2}$$

Solution

The given expression can be written as $$\frac{57}{17}\div\frac{75}{34}-\frac{34}{25}$$=$$?^{2}$$

$$?^{2}= \frac{57}{17}*\frac{34}{75}-\frac{34}{25}$$

$$?^{2}=\frac{2*19}{25}-\frac{34}{25}$$

$$?^{2}=\frac{38}{25}-\frac{34}{25}$$

$$?^{2}=\frac{4}{25}$$

$$=> ?= \frac{2}{5}$$

Option A is the right answer.

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