Question 142

$$sin^{2}$$ $$\theta - 3 sin \theta + 2 = 0$$ will be true if

Solution

Given that $$sin^{2}$$ θ - 3 sin θ + 2 = 0

$$sin^{2}$$ θ - 2 sin θ - sin θ + 2 = 0

sin θ (sin θ - 2) - 1 (sin θ - 2) = 0

(sin θ - 2)(sin θ - 1) = 0

here,

sin θ = 2 is not a possible value as max value of sin θ = 1

and so sin θ = 1

and sin θ takes value 1 at θ = 90 degree

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