$$9\frac{3}{4}\div\left[2\frac{1}{6}+\left\{4\frac{1}{3}-\left(2\frac{1}{2}+\frac{3}{4}\right)\right\}\right]$$ is equal to:

A

4

B

3

C

$$\frac{15}{4}$$

D

$$\frac{17}{4}$$