Question 141

50 boxes with equal weights were loaded in a ship. 5 more boxes each weighing 105 kg were later added, making the average weight of all the 55 boxes as 95 kg. The weight of each of the 50 boxes first loaded is

Solution

Let weight of each box be $$x$$ kg

=> Total weight of 50 boxes = $$50x$$ kg

Total weight of 5 additional boxes = 105*5 = 525 kg

Acc to ques :

=> $$\frac{50x + 525}{55} = 95$$

=> $$50x + 525 = 5225$$

=> $$x = \frac{4700}{50}$$

=> $$x = 94$$ kg

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