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Question 140
PQR is a right angled triangle where P and R are the points (2, 4) and (6, 10) respectively and $$\angle Q = 90^\circ$$. Then the circumcentre of the triangle is
Solution
In a right-angled triangle, circumcentre is the centre of the hypotenuse.
Hence circumcentre = $$\frac{\left(6+2\right)}{2},\ \frac{\left(10+4\right)}{2}=\left(4,7\right)$$
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