Question 139

The area (in sq. units) of the triangle formed by points (2, 3), (3, 4) and (4, 2) is

Solution

Area of triangle formed by points (2, 3), (3, 4) and (4, 2) = $$\frac{1}{2}\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|$$

$$=\frac{1}{2}\left|2\left(4-2\right)+3\left(2-3\right)+4\left(3-4\right)\right|$$

$$=\frac{1}{2}\left|2\left(2\right)+3\left(-1\right)+4\left(-1\right)\right|$$

$$=\frac{1}{2}\left|4-3-4\right|$$

$$=\frac{1}{2}\left|-3\right|$$

$$=\frac{3}{2}$$


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