Question 140
In the given figure, what is the value of $$\angle1+\angle2+\angle3+\angle4+\angle5+\angle6+\angle7+\angle8+\angle9+\angle10$$?
Solution
Now
1+8+3 =180 (Sum of all angles of a triangle )
4+7+2 =180 (Sum of all angles of a triangle )
6+10+5+9 =360 (Sum of all angles of a quadrilateral )
Now adding all we get
1+2+3+4+5+6+7+8+9+10 = 180+180+360 =720
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