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If $$\triangle ABC$$, $$\angle B=90^\circ$$, AB = 8 cm and BC = 15 cm then Sin c = ?
Given : AB = 8 cm and BC = 15 cm
To find : $$sin\ C=?$$
Solution : $$sin\ C=\frac{AB}{BC}$$
=> $$sin\ C=\frac{8}{15}$$
=> Ans - (C)
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