Question 140

If ΔABC is right angled at B, AB = 30 and ∠ACB = 60°, then what is the value of AC?

Solution

It is given that $$\triangle$$ ABC is a right angled at B, AB = 30 cm and $$\angle C=60^\circ$$

Now, in right $$\triangle$$ ABC,

=> $$sin(\angle C)=\frac{AB}{AC}$$

=> $$sin(60^\circ)=\frac{30}{AC}$$

=> $$\frac{\sqrt3}{2}=\frac{30}{AC}$$

=> $$AC=\frac{2}{\sqrt3}\times30=20\sqrt3$$ cm

=> Ans - (B)

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