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Instructions
In each of the following number series, a wrong number is given. FInd out the wrong number.
Solution
$$(3\times2)+3 = 9$$
$$(9\times3)-4 = 23$$
$$(23\times4)+5 = 97$$
$$(97\times5)-6 = 479$$
$$(479\times6)+7 = 2881$$
$$(2881\times7)-8 = 20159$$
Hence, it should be 97 instead of 99.
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