Question 139
Two chords AB and CD of a circle intersect each other at P internally. If AP = 3.5 cm, PC = 5 cm, and DP = 7 cm, then what is the measure of PB?
Solution
As per the given question,
AP=3.5cm, DP=7cm, PC=5cm, PB=?
We know that if two chords internally intersecting each other at point P.
So, $$AP\times PB=CP\times PD$$
Now, substitute the values in the equation,
$$\Rightarrow 3.5 \times PB=5\times 7$$
$$\Rightarrow PB=\dfrac{5\times 7}{3.5}=10cm$$
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