The length of a room is 3 m more than its breadth. If the area of the floor of the room is 70 m, then the perimeter of the floor will be
Let breadth = $$x$$ m
=> Length = $$(x+3)$$ m
=> Area = $$x(x+3)=70$$
=> $$x^2+3x-70=0$$
=> $$x^2+10x-7x-70=0$$
=> $$x(x+10)-7(x+10)=0$$
=> $$(x-7)(x+10)=0$$
=> $$x=7,-10$$
$$\because$$ Breadth cannot be negative, => $$x\neq-10$$
$$\therefore$$ Perimeter = $$2(l+b)$$
= $$2(x+x+3)=4x+6$$
=Â $$4(7)+6=28+6=34$$ m
=> Ans - (D)
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