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If (3, -6), (5, 7) and (13, 4) are the mid point of the sides BC, CA and AB of triangle ABC and if the centroid of the triangle is (a, b), then a + b =
$$\frac{39}{3}$$
$$\frac{26}{3}$$
$$\frac{20}{3}$$
$$\frac{8}{3}$$
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