The value of $$1 - 3 \div 6$$ of $$2 + (4 \div 4 of \frac{1}{4}) \div 8 + (4 \times 8 \div \frac{1}{4}) \times \frac{1}{8}$$ is:

A

$$\frac{69}{4}$$

B

$$-\frac{69}{4}$$

C

$$\frac{7}{4}$$

D

$$-\frac{7}{4}$$