The area of a right angled triangle having base 24 cm and hypotenuse 25 cm is:
Solution
In a right triangle with base 24 and hypotenuse 25 We can say altitude will be $$\sqrt{\ 25^2-24^2}=\sqrt{\ 49}=7$$ Therefore area will be :$$\frac{1}{2}\times\ 7\times\ 24\ =\ 84\ cm^2$$