Question 137

What is the greatest number which divides the numbers 595, 853 and 486 and leaves remainders 3, 2 and 5 respectively?

Solution

Let the required number be x.
When numbers 595, 853 and 486 is divided by x remainders are 3, 2 and 5 respectively.
So 595 - 3 = 592, 853 - 2 = 851 and 486 - 5 = 481 must be divisible by x
Greatest value of ‘x’ = HCF(592, 851, 481) = 37
Hence, option D is the right answer.

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