AP ICET 26th April 2019 Shift-2

Question 137

The perimeter (in cms) of a Rhombus whose diagonals are 9 cm and 12 cm is

Solution

We know diagonals bisect each other perpendicularly

Hence side of the rhombus would be $$\sqrt{\ 4.5^2+6^2}=7.5$$

Perimeter = 4*7.5 = 30


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